1] A starts 3 minutes after B for a place 4.5 km distant. B on reaching his destination immediately returns and after walking a km meets A.If A can cover 1km in 18 mins what is B's speed?
a]6 km/hr b]7 km/hr c]8 km/hr d] 5 km/hr
A covers 3.5 km before meeting B.So time taken for it is = [18 * 3.5] + 3 = 66 mins
B covers 5.5 km [11/2 km] before meeting A in 66 mins i.e., [66/60] hours = time taken
B's speed = [d/t] = [ 11/2 ]/ [11/10] = 5 km/hr
a]6 km/hr b]7 km/hr c]8 km/hr d] 5 km/hr
A covers 3.5 km before meeting B.So time taken for it is = [18 * 3.5] + 3 = 66 mins
B covers 5.5 km [11/2 km] before meeting A in 66 mins i.e., [66/60] hours = time taken
B's speed = [d/t] = [ 11/2 ]/ [11/10] = 5 km/hr
can you explain me how a covers 3.5km
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ReplyDeleteWould you please explain again?
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